OCR GCSE Maths

Revision Notes

Types of Graphs

Test Yourself

Types of Graphs

Why do we need to know what graphs look like?

  • 图中使用various aspects of mathematics – but in the real world they can take on specific meanings
  • For example alinear (straight line)graph could be the path a ship needs to sail along to get from one port to another
  • Anexponentialgraph (y=kx{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y equals k to the power of x" style="vertical-align:-6px;height:23px;width:46px" loading="lazy">) can be used to model population growth – for instance to monitor wildlife conservation projects

What are the shapes of graphs that we need to know?

  • Recalling facts alone won’t do much for boosting your GCSE Mathematics grade!
  • But being familiar with the general shapes of graphs will help you quickly recognise the sort of maths you are dealing with and features of the graph a question may refer to
  • Below the basic form of the five types of function (other thantrig graphs) you need to recognise;
    • linear(y=±x{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y equals plus-or-minus x" style="vertical-align:-6px;height:22px;width:54px" loading="lazy">)
    • quadratic(y=±x2{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y equals plus-or-minus x squared" style="vertical-align:-6px;height:23px;width:61px" loading="lazy">)
    • cubic(y=±x3{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y equals plus-or-minus x cubed" style="vertical-align:-6px;height:23px;width:61px" loading="lazy">)
    • reciprocal(y=±1x{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y equals plus-or-minus 1 over x" style="vertical-align:-17px;height:47px;width:62px" loading="lazy">)
    • exponential(y=k±x{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y equals k to the power of plus-or-minus x end exponent" style="vertical-align:-6px;height:23px;width:55px" loading="lazy">)

w2DxgV4S_edexcel-igcse-3-graphs-types-of-graphs

  • In addition, you need to recognise the three basic trigonometric graphs- but these are dealt with in the next section

Worked example

Match the graphs to the equations.

Graphs:

A

screen-shot-2022-11-28-at-9-55-22-am

B

screen-shot-2022-11-28-at-9-55-27-am

C

screen-shot-2022-11-28-at-9-55-34-am

D

screen-shot-2022-11-28-at-9-55-39-am

E

screen-shot-2022-11-28-at-9-55-44-am

Equations:

(1)y=0.6x+2{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y equals 0.6 x plus 2" style="vertical-align:-6px;height:22px;width:87px" loading="lazy">, (2)y=3x{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y equals 3 to the power of x" style="vertical-align:-6px;height:23px;width:45px" loading="lazy">, (3)y=-0.7x3{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y equals negative 0.7 x cubed" style="vertical-align:-6px;height:23px;width:85px" loading="lazy">, (4)y=4x{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y equals 4 over x" style="vertical-align:-17px;height:47px;width:46px" loading="lazy">, (5)y=-x2+3x+2{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y equals negative x squared plus 3 x plus 2" style="vertical-align:-6px;height:23px;width:124px" loading="lazy">

Starting with the equations,
(1)is a linear equation (y=mx+c) so matches the only straight line, graph(D)
(2)is an exponential equation with a positive coefficient so matches graph(A)
(3)
is a cubic equation with a negative coefficient so matches graph(E)
(4)
is a reciprocal equation (notice that it takes the same form asinverse proportion) with a positive coefficient so matches graph(B)
(5)is a quadratic equation with a negative coefficient so matches graph(C)

Graph (A) → Equation (2)

Graph (B) → Equation (4)

Graph (C) → Equation (5)

Graph (D) → Equation (1)

Graph (E) → Equation (3)

Quadratic Graphs

A quadratic is a function of the formy=ax2+bx+c{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y equals a x squared plus b x plus c" style="vertical-align:-6px;height:23px;width:115px" loading="lazy">wherea{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="a" style="vertical-align:-6px;height:22px;width:10px" loading="lazy">is not zero
They are a very common type of function in mathematics, so it is important to know their key features

What does a quadratic graph look like?

  • The shape made by a quadratic graph is known as aparabola
  • The parabola shape of a quadratic graph can either look like a “u-shape” or an “n-shape”
    • A quadratic with apositive coefficientofx2{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="x squared" style="vertical-align:-6px;height:23px;width:18px" loading="lazy">will be au-shape
    • A quadratic with anegative coefficientofx2{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="x squared" style="vertical-align:-6px;height:23px;width:18px" loading="lazy">will be ann-shape
  • A quadratic will always cross they{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y" style="vertical-align:-6px;height:22px;width:11px" loading="lazy">-axis
  • A quadratic may cross thex{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="x" style="vertical-align:-6px;height:22px;width:11px" loading="lazy">-axis twice, once, or not at all
    • The points where the graph crosses thex{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="x" style="vertical-align:-6px;height:22px;width:11px" loading="lazy">-axis are called theroots
  • If the quadratic is au-shape, it has aminimum point(the bottom of the u)
  • If the quadratic is ann-shape, it has amaximum point(the top of the n)
  • Minimum and maximum points are both examples ofturning points

Quadratic Graphs Notes Diagram 1

How do I sketch a quadratic graph?

  • We could create a table of values for the function and then plot it accurately, however we often only require a sketch to be drawn, showing just the key features
  • The most important features of a quadratic are
    • Its overall shape; a u-shape or an n-shape
    • Itsy{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y" style="vertical-align:-6px;height:22px;width:11px" loading="lazy">-intercept
    • Itsx{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="x" style="vertical-align:-6px;height:22px;width:11px" loading="lazy">-intercept(s), these are also known as the roots
    • Its minimum or maximum point (turning point)
  • If it is a positive quadratic (a{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="a" style="vertical-align:-6px;height:22px;width:10px" loading="lazy">inax2+bx+c{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="a x squared plus b x plus c" style="vertical-align:-6px;height:23px;width:88px" loading="lazy">is positive) it will be a u-shape
  • If it is a negative quadratic (a{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="a" style="vertical-align:-6px;height:22px;width:10px" loading="lazy">inax2+bx+c{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="a x squared plus b x plus c" style="vertical-align:-6px;height:23px;width:88px" loading="lazy">is negative) it will be an n-shape
  • They{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y" style="vertical-align:-6px;height:22px;width:11px" loading="lazy">-intercept ofy=ax2+bx+c{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y equals a x squared plus b x plus c" style="vertical-align:-6px;height:23px;width:115px" loading="lazy">will be0, c{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="open parentheses 0 comma space c close parentheses" style="vertical-align:-6px;height:22px;width:40px" loading="lazy">
  • The roots, or thex{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="x" style="vertical-align:-6px;height:22px;width:11px" loading="lazy">-intercepts will be the solutions toy=0{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y equals 0" style="vertical-align:-6px;height:22px;width:37px" loading="lazy">;ax2+bx+c=0{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="a x squared plus b x plus c equals 0" style="vertical-align:-6px;height:23px;width:114px" loading="lazy">
    • You can solve a quadratic by factorising, completing the square, or using the quadratic formula
    • There may be 2, 1, or 0 solutions and therefore 2, 1, or 0 roots
  • The minimum or maximum point of a quadratic can be found by;
    • Completing the square
      • Once the quadratic has been written in the formy=px-q2+r{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y equals p open parentheses x minus q close parentheses squared plus r" style="vertical-align:-6px;height:23px;width:118px" loading="lazy">, the minimum or maximum point is given byq, r{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="open parentheses q comma space r close parentheses" style="vertical-align:-6px;height:22px;width:39px" loading="lazy">
      • Be careful with the sign of thex-coordinate. E.g. if the equation isy=x-32+2{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y equals open parentheses x minus 3 close parentheses squared plus 2" style="vertical-align:-6px;height:23px;width:109px" loading="lazy">then the minimum point is3, 2{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="open parentheses 3 comma space 2 close parentheses" style="vertical-align:-6px;height:22px;width:40px" loading="lazy">but if the equation isy=x+32+2{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y equals open parentheses x plus 3 close parentheses squared plus 2" style="vertical-align:-6px;height:23px;width:109px" loading="lazy">then the minimum point is-3, 2{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="开括号- 3逗号space 2 close parentheses" style="vertical-align:-6px;height:22px;width:53px" loading="lazy">

Worked example

a)

Sketch the graph ofy=x2-5x+6{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y equals x squared minus 5 x plus 6" style="vertical-align:-6px;height:23px;width:107px" loading="lazy">showing thex{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="x" style="vertical-align:-6px;height:22px;width:11px" loading="lazy">andy{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y" style="vertical-align:-6px;height:22px;width:11px" loading="lazy">intercepts

It is a positive quadratic, so will be a u-shape

The+c{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="plus c" style="vertical-align:-6px;height:22px;width:23px" loading="lazy">最后是y{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y" style="vertical-align:-6px;height:22px;width:11px" loading="lazy">-intercept, so this graph crosses they{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y" style="vertical-align:-6px;height:22px;width:11px" loading="lazy">-axis at(0,6)

Factorise

y=x-2x-3{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y equals open parentheses x minus 2 close parentheses open parentheses x minus 3 close parentheses" style="vertical-align:-6px;height:22px;width:124px" loading="lazy">

Solvey=0{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y equals 0" style="vertical-align:-6px;height:22px;width:37px" loading="lazy">

x-2x-3=0{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="open parentheses x minus 2 close parentheses open parentheses x minus 3 close parentheses equals 0" style="vertical-align:-6px;height:22px;width:123px" loading="lazy">

x=2 or x=3{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="x equals 2 space or space x equals 3" style="vertical-align:-6px;height:22px;width:96px" loading="lazy">

So the roots of the graph are

(2,0) and (3,0)

cie-igcse-quadratic-graphs-we-1

b)

Sketch the graph ofy=x2-6x+13{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y equals x squared minus 6 x plus 13" style="vertical-align:-6px;height:23px;width:116px" loading="lazy">showing they{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y" style="vertical-align:-6px;height:22px;width:11px" loading="lazy">-intercept and the turning point

It is a positive quadratic, so will be a u-shape

The+c{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="plus c" style="vertical-align:-6px;height:22px;width:23px" loading="lazy">最后是y{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y" style="vertical-align:-6px;height:22px;width:11px" loading="lazy">-intercept, so this graph crosses the y-axis at

(0,13)

We can find the minimum point (it will be a minimum as it is a positive quadratic) by completing the square:

x2-6x+13=x-32-9+13=x-32+4{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="x squared minus 6 x plus 13 equals open parentheses x minus 3 close parentheses squared minus 9 plus 13 equals open parentheses x minus 3 close parentheses squared plus 4" style="vertical-align:-6px;height:23px;width:320px" loading="lazy">

This shows that the minimum point will be

(3,4)

As theminimumpoint is above thex{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="x" style="vertical-align:-6px;height:22px;width:11px" loading="lazy">-axis, this means the graph will not cross thex{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="x" style="vertical-align:-6px;height:22px;width:11px" loading="lazy">-axis i.e. it has no roots

We could also show that there are no roots by trying to solvex2-6x+13=0{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="x squared minus 6 x plus 13 equals 0" style="vertical-align:-6px;height:23px;width:115px" loading="lazy">

If we use the quadratic formula, we will find thatx{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="x" style="vertical-align:-6px;height:22px;width:11px" loading="lazy">is the square root of a negative number, which is not a real number, which means there are no real solutions, and hence no roots

cie-igcse-quadratic-graphs-we-2

c)

Sketch the graph ofy=-x2-4x-4{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y equals negative x squared minus 4 x minus 4" style="vertical-align:-6px;height:23px;width:124px" loading="lazy">showing the root(s),y{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y" style="vertical-align:-6px;height:22px;width:11px" loading="lazy">-intercept, and turning point

It is a negative quadratic, so will be an n-shape

The+c{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="plus c" style="vertical-align:-6px;height:22px;width:23px" loading="lazy">最后是y{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y" style="vertical-align:-6px;height:22px;width:11px" loading="lazy">-intercept, so this graph crosses they{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y" style="vertical-align:-6px;height:22px;width:11px" loading="lazy">-axis at (0, -4)

We can find the maximum point (it will be a maximum as it is a negative quadratic) by completing the square:

-x2-4x-4=-1x2+4x+4=-1x+22-4+4=-x+22{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="negative x squared minus 4 x minus 4 equals negative 1 open parentheses x squared plus 4 x plus 4 close parentheses equals negative 1 open parentheses open parentheses x plus 2 close parentheses squared minus 4 plus 4 close parentheses equals negative open parentheses x plus 2 close parentheses squared" style="vertical-align:-6px;height:23px;width:478px" loading="lazy">

This shows that the maximum point will be

(-2, 0)

As the maximum is on thex{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="x" style="vertical-align:-6px;height:22px;width:11px" loading="lazy">-axis, there isonly one root

We could also show that there is only one root by solving-x2-4x-4=0{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="negative x squared minus 4 x minus 4 equals 0" style="vertical-align:-6px;height:23px;width:119px" loading="lazy">

If you use the quadratic formula, you will find that the two solutions forx{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="x" style="vertical-align:-6px;height:22px;width:11px" loading="lazy">are the same number; in this case -2

cie-igcse-quadratic-graphs-we-3

Drawing Graphs Using a Table

How do we draw a graph using a table of values in a non-calculator exam?

  • Before you start, think what the graph might look like- see the previous notes on being familiar with shapes of graphs
  • Using the rules of BIDMAS/ order of operations, substitute eachx{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="x" style="vertical-align:-6px;height:22px;width:11px" loading="lazy">- value into the given function
  • PLOT POINTS and join with a SMOOTH CURVE
  • If there are any points that don't seem to fit with the shape of the rest of the curve, check your calculations for them again!

How do we draw a graph using a table of values in a calculator exam?

  • Before you start, think what the graph might look like – see the previous notes on being familiar with shapes of graphs
  • Find theTABLEfunction on your CALCULATOR
  • Enter the FUNCTION – f(x)

    (use ALPHA button andxorX, depending on make/model)

    (Press = when finished)

    (If you are asked for another function, g(x), just press enter again)
  • EnterStart,EndandStep(gap betweenxvalues)
  • Press = and scroll up and down to seeyvalues
  • PLOT POINTS and join with a SMOOTH CURVE
  • To avoid errors always put negative numbers in brackets and use the (-) key rather than the subtraction key
  • If your calculator does not have a TABLE function, then you will have to work out eachyvalue separately using the normal mode on your calculator

Exam Tip

  • 当使用计算器的表函数,double-check that your calculator'sy-values are the same as any that are given in the question

Worked example

Calculator Allowed

(a)
Complete the table of values for the functiony=x3-5x+2{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y equals x cubed minus 5 x plus 2" style="vertical-align:-6px;height:23px;width:107px" loading="lazy">.

x{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="x" style="vertical-align:-6px;height:22px;width:11px" loading="lazy"> -3{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="negative 3" style="vertical-align:-6px;height:22px;width:23px" loading="lazy"> -2{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="negative 2" style="vertical-align:-6px;height:22px;width:23px" loading="lazy"> -1{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="negative 1" style="vertical-align:-6px;height:22px;width:23px" loading="lazy"> 0{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="0" style="vertical-align:-6px;height:22px;width:10px" loading="lazy"> 1{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="1" style="vertical-align:-6px;height:22px;width:10px" loading="lazy"> 2{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="2" style="vertical-align:-6px;height:22px;width:10px" loading="lazy"> 3{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="3" style="vertical-align:-6px;height:22px;width:10px" loading="lazy">
y{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y" style="vertical-align:-6px;height:22px;width:11px" loading="lazy"> 4{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="4" style="vertical-align:-6px;height:22px;width:10px" loading="lazy"> 14{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="14" style="vertical-align:-6px;height:22px;width:19px" loading="lazy">

Use the TABLE function on your calculator for
fx=x2-x-6{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="f open parentheses x close parentheses equals x squared minus x minus 6" style="vertical-align:-6px;height:23px;width:119px" loading="lazy">, starting at -3, ending at 3 and with steps of 1
If your calculator does not have a TABLE function then substitute the values of x{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="x" style="vertical-align:-6px;height:22px;width:11px" loading="lazy"> into the function one by one for the missing values, being careful to put negative numbers in brackets, e.g.
x=-3, y=-33-5-3+2=-10{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="x equals negative 3 comma space y equals open parentheses negative 3 close parentheses cubed minus 5 open parentheses negative 3 close parentheses plus 2 equals negative 10" style="vertical-align:-6px;height:23px;width:269px" loading="lazy">

x{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="x" style="vertical-align:-6px;height:22px;width:11px" loading="lazy"> -3{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="negative 3" style="vertical-align:-6px;height:22px;width:23px" loading="lazy"> -2{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="negative 2" style="vertical-align:-6px;height:22px;width:23px" loading="lazy"> -1{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="negative 1" style="vertical-align:-6px;height:22px;width:23px" loading="lazy"> 0{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="0" style="vertical-align:-6px;height:22px;width:10px" loading="lazy"> 1{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="1" style="vertical-align:-6px;height:22px;width:10px" loading="lazy"> 2{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="2" style="vertical-align:-6px;height:22px;width:10px" loading="lazy"> 3{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="3" style="vertical-align:-6px;height:22px;width:10px" loading="lazy">
y{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y" style="vertical-align:-6px;height:22px;width:11px" loading="lazy"> -10{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="bold minus bold 10" style="vertical-align:-6px;height:22px;width:35px" loading="lazy"> 4{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="4" style="vertical-align:-6px;height:22px;width:10px" loading="lazy"> 6{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="bold 6" style="vertical-align:-6px;height:22px;width:11px" loading="lazy"> 2{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="bold 2" style="vertical-align:-6px;height:22px;width:11px" loading="lazy"> -2{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="bold minus bold 2" style="vertical-align:-6px;height:22px;width:25px" loading="lazy"> 0{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="bold 0" style="vertical-align:-6px;height:22px;width:11px" loading="lazy"> 14{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="14" style="vertical-align:-6px;height:22px;width:19px" loading="lazy">

(b)
On the grid provided, draw the graph ofy=x3-5x+2{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="y equals x cubed minus 5 x plus 2" style="vertical-align:-6px;height:23px;width:107px" loading="lazy">for values ofx{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="x" style="vertical-align:-6px;height:22px;width:11px" loading="lazy">from-3{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="negative 3" style="vertical-align:-6px;height:22px;width:23px" loading="lazy">to3{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="3" style="vertical-align:-6px;height:22px;width:10px" loading="lazy">.


Carefully plot the points from your table of values in (a) on the grid, noting the different scales on the and axes

For example, the first column represents the point-3,-10{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" class="Wirisformula" role="math" alt="开括号- 3逗号negative 10 close parentheses" style="vertical-align:-6px;height:22px;width:75px" loading="lazy">

After plotting the points, join them with a smooth curve- do not use a ruler!

2-14-drawing-graphs

It is best practice to label the curve with its equation

Daniel Ingham

Author:Daniel Ingham

Daniel has taught maths for over 10 years in a variety of settings, covering GCSE, IGCSE, A-level and IB. The more he taught maths, the more he appreciated its beauty. He loves breaking tricky topics down into a way they can be easily understood by students, and creating resources that help to do this.